Реферат: Разработка и исследование имитационной модели разветвленной СМО (системы массового обслуживания) в среде VB5

MAX = +4.4%           MAX = +17%            MAX = +10%            MAX = +3.2%

MIN = -2.0%             MIN = -11%              MIN = -6.5%             MIN = -7.2%

MAX = +1%              MAX = +4.6%           MAX = +2.1%           MAX = +3.3%

MIN = -1.8%             MIN = -12.7%           MIN = -3.6%             MIN = -4.1%

MAX = +1.9%           MAX = +15.3%         MAX = +5.9%           MAX = +2.2%

MIN = -0.8%             MIN = -10%              MIN = -4%                MIN = -5.2%

13. 4 станции, 32000 заявок, 10 экспериментов

1 — 2 = 0.9;       1 — 3 = 0.1;       2 — 4 = 1;          3 — 4 = 1;

отбраковки нет

Ta = 5, Ts(1) = 3, Ts(2) = 3, Ts(3) = 3, Ts(4) = 3

По формулам:

MAX = +6%              MAX = +4.2%           MAX = +22%            MAX = +3.6%

MIN = -5.1%             MIN = -4%                MIN = -21.5%           MIN = -6.6%

MAX = +2.4%           MAX = +1.7%           MAX = +1.8%           MAX = +3.3%

MIN = -4%                MIN = -2.3%             MIN = -2.3%             MIN = -2.1%

MAX = +3.9%           MAX = +2.5%           MAX = +2.2%           MAX = +2.3%

MIN = -3.3%             MIN = -2.6%             MIN = -5.2%             MIN = -4.5%

14. 4 станции, 32000 заявок, 10 экспериментов

1 — 2 = 0.1;       1 — 3 = 0.9;       2 — 4 = 1;          3 — 4 = 1;

отбраковки нет

Ta = 5, Ts(1) = 3, Ts(2) = 3, Ts(3) = 3, Ts(4) = 3

По формулам:

MAX = +5.6%           MAX = +14.1%         MAX = +3.9%           MAX = +3.8%

MIN = -5.3%             MIN = -15.2%           MIN = -5.2%             MIN = -4%

MAX = +2.5%           MAX = +2.5%           MAX = +2%              MAX = +1.4%

MIN = -1.9%             MIN = -4%                MIN = -1.2%             MIN = -1.2%

MAX = +3.9%           MAX = +5.1%           MAX = +2.6%           MAX = +2.4%

MIN = -3.4%             MIN = -3.9%             MIN = -3.4%             MIN = -2.5%

15. 4 станции, 32000 заявок, 10 экспериментов

1 — 2 = 0.5;       1 — 3 = 0.5;       2 — 4 = 1;          3 — 4 = 1;

отбраковки нет

Ta = 5, Ts(1) = 3, Ts(2) = 3, Ts(3) = 3, Ts(4) = 3

По формулам:

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